# std::is_base_of

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< cpp‎ | types

Defined in header `<type_traits>` |  |
template< class Base, class Derived > struct is_base_of; |  | (since C++11)

If `Derived` is derived from `Base` or if both are the same non-union class (in both cases ignoring cv-qualification), provides the member constant `value` equal to true. Otherwise `value` is false.

If both `Base` and `Derived` are non-union class types, and they are not the same type (ignoring cv-qualification), `Derived` shall be a complete type; otherwise the behavior is undefined.

### Helper variable template

template< class Base, class Derived > inline constexpr bool is_base_of_v = is_base_of<Base, Derived>::value; |  | (since C++17)

## Inherited from std::integral_constant

### Member constants

value [static] | true if `Derived` is derived from `Base` or if both are the same non-union class (in both cases ignoring cv-qualification), false otherwise (public static member constant)

### Member functions

operator bool | converts the object to bool, returns `value` (public member function)
operator() (C++14) | returns `value` (public member function)

### Member types

Type | Definition
`value_type` | `bool`
`type` | std::integral_constant <bool, value>

### Notes

`std::is_base_of<A, B>::value` is true even if `A` is a private, protected, or ambiguous base class of `B`. In many situations, std::is_convertible <B*, A*> is the more appropriate test.

Although no class is its own base, std::is_base_of<T, T>::value is true because the intent of the trait is to model the "is-a" relationship, and T is a T. Despite that, std::is_base_of<int, int>::value is false because only classes participate in the relationship that this trait models.

### Possible Implementation

    namespace details {
        template <typename Base> std::true_type is_base_of_test_func(const volatile Base*);
        template <typename Base> std::false_type is_base_of_test_func(const volatile void*);
        template <typename Base, typename Derived>
        using pre_is_base_of = decltype(is_base_of_test_func<Base>(std::declval<Derived*>()));

        // with <experimental/type_traits>:
        // template <typename Base, typename Derived>
        // using pre_is_base_of2 = std::experimental::detected_or_t<std::true_type, pre_is_base_of, Base, Derived>;
        template <typename Base, typename Derived, typename = void>
        struct pre_is_base_of2 : public std::true_type { };
        // note std::void_t is a C++17 feature
        template <typename Base, typename Derived>
        struct pre_is_base_of2<Base, Derived, std::void_t<pre_is_base_of<Base, Derived>>> :
            public pre_is_base_of<Base, Derived> { };
    }

    template <typename Base, typename Derived>
    struct is_base_of :
        public std::conditional_t<
            std::is_class<Base>::value && std::is_class<Derived>::value,
            details::pre_is_base_of2<Base, Derived>,
            std::false_type
        > { };

### Example

Run this code

    #include <iostream>
    #include <type_traits>

    class A {};

    class B : A {};

    class C {};

    int main()
    {
        std::cout << std::boolalpha;
        std::cout << "a2b: " << std::is_base_of<A, B>::value << '\n';
        std::cout << "b2a: " << std::is_base_of<B, A>::value << '\n';
        std::cout << "c2b: " << std::is_base_of<C, B>::value << '\n';
        std::cout << "same type: " << std::is_base_of<C, C>::value << '\n';
    }

Output:

    a2b: true
    b2a: false
    c2b: false
    same type: true

### See also

is_convertibleis_nothrow_convertible (C++11)(C++20) | checks if a type can be converted to the other type (class template)

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