FAQ
Below are some Frequently Asked Questions about cpp11. If you have a
question that you think would fit well here please open an
issue.
1. What are the underlying types of cpp11 objects?
cpp11::integers |
int |
cpp11::doubles |
double |
cpp11::logicals |
cpp11::r_bool |
cpp11::strings |
cpp11::r_string |
cpp11::raws |
uint8_t |
cpp11::list |
SEXP |
2. How do I add elements to a named list?
Use the push_back()
method with the named literal
syntax. The named literal syntax is defined in the
cpp11::literals
namespace.
#include <cpp11.hpp>
[[cpp11::register]]
cpp11::list foo_push() {
using namespace cpp11::literals;
cpp11::writable::list x;
x.push_back({"foo"_nm = 1});
return x;
}
3. Does cpp11 support default arguments?
cpp11 does not support default arguments, while convenient they would
require more complexity to support than is currently worthwhile. If you
need default argument support you can use a wrapper function around your
cpp11 registered function. A common convention is to name the internal
function with a trailing _
.
#include <cpp11.hpp>
[[cpp11::register]]
double add_some_(double x, double amount) {
return x + amount;
}
add_some <- function(x, amount = 1) {
add_some_(x, amount)
}
add_some(1)
#> [1] 2
add_some(1, amount = 5)
#> [1] 6
4. How do I create a new empty list?
Define a new writable list object.
cpp11::writable::list x;
5. How do I retrieve (named) elements from a named vector/list?
Use the []
accessor function.
x["foo"]
6. How can I tell whether a vector is named?
Use the named()
method for vector classes.
#include <cpp11.hpp>
[[cpp11::register]]
bool is_named(cpp11::strings x) {
return x.named();
}
is_named("foo")
#> [1] FALSE
is_named(c(x = "foo"))
#> [1] TRUE
7. How do I return a cpp11::writable::logicals
object
with only a FALSE
value?
You need to use list
initialization with {}
to create the object.
#include <cpp11.hpp>
[[cpp11::register]]
cpp11::writable::logicals my_false() {
return {FALSE};
}
[[cpp11::register]]
cpp11::writable::logicals my_true() {
return {TRUE};
}
[[cpp11::register]]
cpp11::writable::logicals my_both() {
return {TRUE, FALSE, TRUE};
}
my_false()
#> [1] FALSE
my_true()
#> [1] TRUE
my_both()
#> [1] TRUE FALSE TRUE
8. How do I create a new empty environment?
To do this you need to call the base::new.env()
function
from C++. This can be done by creating a cpp11::function
object and then calling it to generate the new environment.
#include <cpp11.hpp>
[[cpp11::register]]
cpp11::environment create_environment() {
cpp11::function new_env(cpp11::package("base")["new.env"]);
return new_env();
}
9. How do I assign and retrieve values in an environment? What
happens if I try to get a value that doesn’t exist?
Use []
to retrieve or assign values from an environment
by name. If a value does not exist it will return
R_UnboundValue
.
#include <cpp11.hpp>
[[cpp11::register]]
bool foo_exists(cpp11::environment x) {
return x["foo"] != R_UnboundValue;
}
[[cpp11::register]]
void set_foo(cpp11::environment x, double value) {
x["foo"] = value;
}
x <- new.env()
foo_exists(x)
#> [1] FALSE
set_foo(x, 1)
foo_exists(x)
#> [1] TRUE
10. How can I create a cpp11:raws
from a
std::string
?
There is no built in way to do this. One method would be to
push_back()
each element of the string individually.
#include <cpp11.hpp>
[[cpp11::register]]
cpp11::raws push_raws() {
std::string x("hi");
cpp11::writable::raws out;
for (auto c : x) {
out.push_back(c);
}
return out;
}
11. How can I create a std::string
from a
cpp11::writable::string
?
Because C++ does not allow for two implicit cast, explicitly cast to
cpp11::r_string
first.
#include <cpp11.hpp>
#include <string>
[[cpp11::register]]
std::string my_string() {
cpp11::writable::strings x({"foo", "bar"});
std::string elt = cpp11::r_string(x[0]);
return elt;
}
12. What are the types for C++ iterators?
The iterators are ::iterator
classes contained inside
the vector classes. For example the iterator for
cpp11::doubles
would be
cpp11::doubles::iterator
and the iterator for
cpp11::writable::doubles
would be
cpp11::writable::doubles::iterator
.
13. My code has using namespace std
, why do I still
have to include std::
in the signatures of
[[cpp11::register]]
functions?
The using namespace std
directive will not be included
in the generated code of the function signatures, so they still need to
be fully qualified. However you will not need to qualify the
type names within those functions.
The following won’t compile
#include <cpp11.hpp>
#include <string>
using namespace std;
[[cpp11::register]]
string foobar() {
return string("foo") + "-bar";
}
But this will compile and work as intended
#include <cpp11.hpp>
#include <string>
using namespace std;
[[cpp11::register]]
std::string foobar() {
return string("foo") + "-bar";
}
14. How do I modify a vector in place?
In place modification breaks the normal semantics of R code. In
general it should be avoided, which is why cpp11::writable
classes always copy their data when constructed.
However if you are positive in-place modification is
necessary for your use case you can use the move constructor to do
this.
#include <cpp11.hpp>
[[cpp11::register]]
void add_one(cpp11::sexp x_sexp) {
cpp11::writable::integers x(std::move(x_sexp.data()));
for (auto&& value : x) {
++value;
}
}
x <- c(1L, 2L, 3L, 4L)
.Internal(inspect(x))
#> @111e43e08 13 INTSXP g0c2 [REF(2)] (len=4, tl=0) 1,2,3,4
add_one(x)
.Internal(inspect(x))
#> @111e43e08 13 INTSXP g0c2 [MARK,REF(6)] (len=4, tl=0) 2,3,4,5
x
#> [1] 2 3 4 5